## Reversing a number

I was working through a programming challenge I found on Reddit and it seemed easy enough: Find all numbers less than \$10^n\$ where the number and its reverse (the reverse of \$123\$ is \$321\$) are both divisible by \$7\$ and then sum them all together. def challenge_229(power): numbers = [] for x in range(0, 10**power, … Read more