What would happen if I made something – CMYK 100

It would literally be:

C: 100
M: 100
Y: 100
K: 100

For a total of 400% color

I know you’re never supposed to go over 300… but

How would this affect:

  • The way it looks on my screen.

  • The way it gets printed.

(just for fun)

  • If I went down to the hardware store and told them I wanted that code made into a paint and then painted my walls with it, what would that be like (would it be an extremely black room – maybe get something close to Vantablack, or would it just look like a regular black wall etc.)


I can’t really claim to know much of anything about mixing house paint…. It’s my understanding though that the mixing system is more akin to a Pantone mix than a CMYK mix.

On screen, it would be just a black.
It would equate to 0R0G0B so.. black.

—> RGB — > enter image description here

On press.. it’ll get rejected by most prepress departments or at least get changed.

The reason there’s an ink limit for printing is because stock can only soak up so much ink. Just as any paper will only hold so much liquid. Every stock gets to a certain point where it just won’t take any more ink. Therefore drying times increase exponentially. Most printing presses have some drying capabilities. So, they are designed to combat basic drying needs, once you pass 300-310% ink, you’ve got wet puddles of ink sitting on top the stock that just won’t dry without time. If a piece needs drying time that means the press may have to be run much slower than normal and even that pieces may need to be pulled off the press before the next piece slides on top of it and smears everything. It’s really one of those things where the additional 90-100% of ink does not outweigh the problems it creates. There’s not a great deal of benefit to a 100% rich black as opposed to a 100K/40C/20M/20Y rich black, for example.

If it could actually be printed, yes it would be a very deep rich black. Not sure it would border Vantablack.. but definitely dark.

Source : Link , Question Author : WELZ , Answer Author : Scott

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